(2b^2+3b-4)/(b-3)

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Solution for (2b^2+3b-4)/(b-3) equation: 


D( b )

b-3 = 0

b-3 = 0

b-3 = 0

b-3 = 0 // + 3

b = 3

b in (-oo:3) U (3:+oo)

(2*b^2+3*b-4)/(b-3) = 0

2*b^2+3*b-4 = 0

2*b^2+3*b-4 = 0

DELTA = 3^2-(-4*2*4)

DELTA = 41

DELTA > 0

b = (41^(1/2)-3)/(2*2) or b = (-41^(1/2)-3)/(2*2)

b = (41^(1/2)-3)/4 or b = (-(41^(1/2)+3))/4

(b+(41^(1/2)+3)/4)*(b-((41^(1/2)-3)/4)) = 0

((b+(41^(1/2)+3)/4)*(b-((41^(1/2)-3)/4)))/(b-3) = 0

( b+(41^(1/2)+3)/4 )

b+(41^(1/2)+3)/4 = 0 // - (41^(1/2)+3)/4

b = -((41^(1/2)+3)/4)

( b-((41^(1/2)-3)/4) )

b-((41^(1/2)-3)/4) = 0 // + (41^(1/2)-3)/4

b = (41^(1/2)-3)/4

b in { -((41^(1/2)+3)/4), (41^(1/2)-3)/4 }

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